3.13. 队列模拟：烫手山芋
.. Copyright (C) Brad Miller, David Ranum This work is licensed under the Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License. To view a copy of this license, visit http://creativecommons.org/licenses/by-nc-sa/4.0/.
Queue Simulation: Hot Potato ~~~~~~~~~~~~~~~~~~~~~~~~~~~~
One of the typical applications for showing a queue in action is to
simulate a real situation that requires data to be managed in a FIFO
manner. To begin, let’s consider the children’s game hot potato. In this
game (see :ref:Figure 2 <fig_quhotpotato>) children line up in a circle and
pass an item from neighbor to neighbor as fast as they can. At a certain
point in the game, the action is stopped and the child who has the item
(the potato) is removed from the circle. Play continues until only one
child is left.
.. _fig_quhotpotato:
.. figure:: Figures/hotpotato.png :align: center
Figure 2: A Six-Person Game of Hot Potato
This game is a modern-day equivalent of the famous Josephus problem. Based on a legend about the famous first-century historian Flavius Josephus, the story is told that in the Jewish revolt against Rome, Josephus and 39 of his comrades held out against the Romans in a cave. With defeat imminent, they decided that they would rather die than be slaves to the Romans. They arranged themselves in a circle. One man was designated as number one, and proceeding clockwise they killed every seventh man. Josephus, according to the legend, was among other things an accomplished mathematician. He instantly figured out where he ought to sit in order to be the last to go. When the time came, instead of killing himself, he joined the Roman side. You can find many different versions of this story. Some count every third man and some allow the last man to escape on a horse. In any case, the idea is the same.
We will implement a general simulation of Hot Potato. Our program
will input a list of names and a constant, call it “num,” to be used for
counting. It will return the name of the last person remaining after
repetitive counting by num. What happens at that point is up to you.
To simulate the circle, we will use a queue (see
:ref:Figure 3 <fig_qupotatoqueue>). Assume that the child holding the potato will
be at the front of the queue. Upon passing the potato, the simulation
will simply dequeue and then immediately enqueue that child, putting them
at the end of the line. They will then wait until all the others have
been at the front before it will be their turn again. After num
dequeue/enqueue operations, the child at the front will be removed
permanently and another cycle will begin. This process will continue
until only one name remains (the size of the queue is 1).
.. _fig_qupotatoqueue:
.. figure:: Figures/namequeue.png :align: center
Figure 3: A Queue Implementation of Hot Potato
The program is shown in :ref:ActiveCode 1 <lst_josephussim>. A call to the
hot_potato function using 7 as the counting constant returns 'Susan'.
.. _lst_josephussim:
.. activecode:: qujosephussim :caption: Hot Potato Simulation :nocodelens:
from pythonds3.basic import Queue
def hot_potato(name_list, num):
sim_queue = Queue()
for name in name_list:
sim_queue.enqueue(name)
while sim_queue.size() > 1:
for i in range(num):
sim_queue.enqueue(sim_queue.dequeue())
sim_queue.dequeue()
return sim_queue.dequeue()
print(hot_potato(["Bill", "David", "Susan", "Jane", "Kent", "Brad"], 7))
Note that in this example the value of the counting constant is greater
than the number of names in the list. This is not a problem since the
queue acts like a circle and counting continues back at the beginning
until the value is reached. Also, notice that the list is loaded into
the queue such that the first name on the list will be at the front of
the queue. 'Bill' in this case is the first item in the list and
therefore moves to the front of the queue. A variation of this
implementation, described in the exercises, allows for a random counter.
创建日期: 2023年10月10日